Q. Which smallest number should be subtracted from 1936 so that on being divided by 9, 10, 15, every time the remainder is 7?
A) 93
B) 46
C) 76
D) 39
✔ Correct Answer: 39
Exam Insight
To solve this, we find the least common multiple (LCM) of 9, 10, and 15, which is 90. Subtracting 7 from 1936 gives 1929. Dividing 1929 by 90, the remainder is checked. The smallest number to subtract is the difference between 1929 and the nearest multiple of 90.