Q. In an acute-angled triangle ABC is Sin(B+A+C)=32 and tan(C+A-B)=1, then C is equal to
A) 67.5°
B) 37.5°
C) 72.5°
D) 52.5°
✔ Correct Answer: 52.5°
Exam Insight
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A) 67.5°
B) 37.5°
C) 72.5°
D) 52.5°
✔ Correct Answer: 52.5°
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